题目地址 https://leetcode.cn/problems/minimum-time-to-complete-all-tasks/description/ 思路 题解 public static int findMinimumTime(int[][] tasks) {//先将数数组进行尾端升序排列Arrays.sort(tasks, (a, b) -> a[1
343. 整数拆分 动归 递归拆 class Solution:def integerBreak(self, n: int) -> int:dp=[0]*(n+1)dp[2]=1for i in range(3,n+1):for j in range(1,i//2+1):dp[i]=max(dp[i],(i-j)*j,dp[i-j]*j)return dp[n] 公式:全拆3,剩1个4