opencv检测图片失焦 python_使用Opencv和python从高分辨率图像中检测和裁剪图像

现场视频分辨率约为4000x3000像素，其图像已显示在附件中。有可能探测到目标，裁剪图像吗？在

有了一些早期的代码，我只能检测到他们的对象，但我面临的问题是在OpenCV中摄像头大便进程

注：图像检测过程使用笔记本电脑网络摄像头，使用以下代码：import cv2

import numpy as np

video = cv2.VideoCapture("output.avi")

_, first_frame = video.read()

x = 210

y = 310

width = 230

height = 115

roi = first_frame[y: y + height, x: x + width]

hsv_roi = cv2.cvtColor(roi, cv2.COLOR_BGR2HSV)

roi_hist = cv2.calcHist([hsv_roi], [0], None, [180], [0, 180])

roi_hist = cv2.normalize(roi_hist, roi_hist, 0, 255, cv2.NORM_MINMAX)

term_criteria = (cv2.TERM_CRITERIA_EPS | cv2.TERM_CRITERIA_COUNT, 10, 1)

print(term_criteria)

while True:

_, frame = video.read()

hsv = cv2.cvtColor(frame, cv2.COLOR_BGR2HSV)

mask = cv2.calcBackProject([hsv], [0], roi_hist, [0, 180], 1)

_, track_window = cv2.meanShift(mask, (x, y, width, height), term_criteria)

x, y, w, h = track_window

cv2.rectangle(frame, (x, y), (x + w, y + h), (0, 255, 0), 2)

cv2.imshow("Mask", mask)

cv2.imshow("Frame", frame)

key = cv2.waitKey(60)

if key == 27:

break

video.release()

cv2.destroyAllWindows()

关于这一点的建议将是一个很大的帮助