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文章目录
- 一、题目
- 二、题解
一、题目
Given a string s of zeros and ones, return the maximum score after splitting the string into two non-empty substrings (i.e. left substring and right substring).
The score after splitting a string is the number of zeros in the left substring plus the number of ones in the right substring.
Example 1:
Input: s = “011101”
Output: 5
Explanation:
All possible ways of splitting s into two non-empty substrings are:
left = “0” and right = “11101”, score = 1 + 4 = 5
left = “01” and right = “1101”, score = 1 + 3 = 4
left = “011” and right = “101”, score = 1 + 2 = 3
left = “0111” and right = “01”, score = 1 + 1 = 2
left = “01110” and right = “1”, score = 2 + 1 = 3
Example 2:
Input: s = “00111”
Output: 5
Explanation: When left = “00” and right = “111”, we get the maximum score = 2 + 3 = 5
Example 3:
Input: s = “1111”
Output: 3
Constraints:
2 <= s.length <= 500
The string s consists of characters ‘0’ and ‘1’ only.
二、题解
class Solution {
public:int maxScore(string s) {int n = s.size();int maxNum = 0;for(int i = 1;i < n;i++){int leftZero = 0,rightOne = 0;for(int j = 0;j < i;j++) if(s[j] == '0') leftZero++;for(int k = i;k < n;k++) if(s[k] == '1') rightOne++;maxNum = max(maxNum,leftZero+rightOne);}return maxNum;}
};
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