c语言编程练习题：7-57 求e的近似值

#include <stdio.h>
#include <math.h>double cal_e(int n){double sum=1.0, term = 1.0;int i;for (i=1; i<=n; i++){term = term * 1.0 / i; //计算当前项的值sum += term; //将当前项加到总和中if (fabs(term) < 1e-16) break; //如果当前项的绝对值已经小于 1e-16，则退出循环}return sum;
}int main(){int n;double sum;if (scanf("%d", &n) != EOF){sum = cal_e(n);printf("%.8f", sum);} else {printf("input n wrong");}return 0;
}  

代码来自：https://yunjinqi.top/article/182