11.11校园赛2-做题代码

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# 输入n
n=int(input())# 对折次数
ans=0
while(True):n=n/2if n >=1:ans+=1else:# 多少次后ans+=1break
print(ans)

# 输入行n,列，m
n,m=map(int,input().split())
# 操作次数
ans=int(input())
# 建立二维表
dp=[[1]*(m+1) for i in range (n+1)]
# print(dp[0][1])
# dp[0][1]=3
# print(dp)# 开始每次操作
for i in range (ans):op=list(map(int,input().split()))for i in range (op[0],op[2]+1):for j in range (op[1],op[3]+1):dp[i][j]=0# print(dp)
# 统计
print(dp)
ans=0
for i in range (1,n+1):for j in range (1,m+1):if dp[i][j]==1:ans+=1
print(ans)

aim='lanqiao'
aim=list(aim)
# print(aim)a=str(input())
# print(a)
a=a.lower()
a=list(a)
# print(a)
# print(aim)
c=1
for i in range (len(aim)):if aim[i]!=a[i]:print('no')c=0break
if c==1:print('yes')

 

# 输入
a=int(input())
b=int(input())
a-=1
# 结果
c=(a+b)%7print(c+1)

number='''
99, 22, 51, 63, 72, 61, 20, 88, 40, 21, 63, 30, 11, 18, 99, 12, 93, 16, 7, 53, 64, 9, 28, 84, 34, 96, 52, 82, 51, 77
'''
# 转化number成list
number=number.replace('\n','')
number=number.split(',')
print(number)
number=list(number)
# 计数
ans=0
# for 1--29
#     for i--29
# 暴力搜索
for i in range (30):for j in range (i+1,30):# if i==j:breakif int(number[i])*int(number[j])>=2022:ans+=1# ans+=1
print(ans)

import datetime
# 开始时间：
start=datetime.date(1900,1,1)
# 结束时间
end=datetime.date(9999,12,31)
# 增加一天# 相同的天数
ans=0
for i in range (999999999):# 开始增加start=start+datetime.timedelta(days=1)# 判断是否结束if start==end:break# 将日期转化成字符串start_=str(start).replace('-','')# 测试# print(start_)# break# 19000102### 转化成int计算# 年各个数字之和：year= int(start_[0])+int(start_[1])+int(start_[2])+int(start_[3])# 测试# print(year)# break# 10data_=int(start_[4])+int(start_[5])+int(start_[6])+int(start_[7])# 判断是否等于if data_==year:ans+=1
# 输出
print(ans)

b=['0','1','2','3','4','5','6','7','8','9']
for i in range (2022 ,3000):a=hex(i)z=a[2:]# print(a)z=list(z)c=0for j in z:if  (j  in  b):breakelse:c+=1if c==3:print(int(a,16))break

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