数据分布不均衡导致性能问题

2023-10-10 18:48

本文主要是介绍数据分布不均衡导致性能问题,希望对大家解决编程问题提供一定的参考价值,需要的开发者们随着小编来一起学习吧!

今晚(2016/04/14)数据库版本11.2.0.4 遇到一个奇葩案例,虽然之前也遇到过非常多奇葩案例,
但是限于当时条件,无法收集案例,谁叫他奶奶的银行,证券,电信不允许泄密啊。还好今晚这个案例可以拿出来分享。故事是这样的,下面这个SQL要跑几十分钟select count(distinct a.user_name), count(distinct a.invest_id)from base_data_login_info@agent awhere a.str_day <= '20160304'and a.str_day >= '20160301'and a.channel_id in (select channel_rlatfrom tb_user_channel a, tb_channel_info bwhere a.channel_id = b.channel_idand a.user_id = 5002)and a.platform = a.platform;Plan hash value: 2367445948-------------------------------------------------------------------------------------------------------------
| Id  | Operation            | Name                 | Rows  | Bytes | Cost (%CPU)| Time     | Inst   |IN-OUT|
-------------------------------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT     |                      |     1 |   130 |   754   (2)| 00:00:10 |        |      |
|   1 |  SORT GROUP BY       |                      |     1 |   130 |            |          |        |      |
|*  2 |   HASH JOIN          |                      |  4067K|   504M|   754   (2)| 00:00:10 |        |      |
|*  3 |    HASH JOIN         |                      | 11535 |   360K|   258   (1)| 00:00:04 |        |      |
|*  4 |     TABLE ACCESS FULL| TB_USER_CHANNEL      | 11535 |   157K|    19   (0)| 00:00:01 |        |      |
|   5 |     TABLE ACCESS FULL| TB_CHANNEL_INFO      | 11767 |   206K|   238   (0)| 00:00:03 |        |      |
|   6 |    REMOTE            | BASE_DATA_LOGIN_INFO |   190K|    17M|   486   (1)| 00:00:06 |  AGENT | R->S |
-------------------------------------------------------------------------------------------------------------Predicate Information (identified by operation id):
---------------------------------------------------2 - access("A"."CHANNEL_ID"="CHANNEL_RLAT")3 - access("A"."CHANNEL_ID"="B"."CHANNEL_ID")4 - filter("A"."USER_ID"=5002)Remote SQL Information (identified by operation id):
----------------------------------------------------6 - SELECT "USER_NAME","INVEST_ID","STR_DAY","CHANNEL_ID","PLATFORM" FROM "BASE_DATA_LOGIN_INFO" "A" WHERE "STR_DAY"<='20160304' AND "STR_DAY">='20160301' AND "PLATFORM" IS NOT NULL (accessing 'AGENT' ) 我瞄了一眼执行计划,初步一看执行计划正常啊。然后赶紧问问dblink的表有多大, in 里面 a, b 分别有多大
tb_user_channel  1W
tb_channel_info  1W
base_data_login_info 19W 过滤剩下4w这些表都不大,最大一个才19w行,怎么也不可能跑几十分钟啊。然后我开始怀疑是不是dblink的表产生了性能问题。
为了排除dblink的表产生性能问题,我让哥们在本地创建一个一模一样的表,结果还是慢,速度根本没有一丁点改变。大爷的,老虎不发威,当我病猫啊。之前都是瞄一眼搞定一个SQL优化。大爷的这次栽了。
以我优化了几万个SQL的功力,恩这个鸟SQL我得花1分钟搞定它。于是我让哥们跑下面这个SQLselect count(*)from base_data_login_info@agent awhere a.str_day <= '20160304'and a.str_day >= '20160301'and a.channel_id in (select channel_rlatfrom tb_user_channel a, tb_channel_info bwhere a.channel_id = b.channel_idand a.user_id = 5002)and a.platform = a.platform;秒杀,没看错,是秒杀 大爷的 奇怪了,这SQL居然秒杀了。 然后我再让哥们跑下面这个SQL select count(a.user_name)from base_data_login_info@agent awhere a.str_day <= '20160304'and a.str_day >= '20160301'and a.channel_id in (select channel_rlatfrom tb_user_channel a, tb_channel_info bwhere a.channel_id = b.channel_idand a.user_id = 5002)and a.platform = a.platform;秒杀,于是再让哥们跑下面SQLselect count(a.user_name), count(a.invest_id)from base_data_login_info@agent awhere a.str_day <= '20160304'and a.str_day >= '20160301'and a.channel_id in (select channel_rlatfrom tb_user_channel a, tb_channel_info bwhere a.channel_id = b.channel_idand a.user_id = 5002)and a.platform = a.platform;秒杀,你大爷的,再跑一下下面这个SQLselect count(distinct a.user_name), count(a.invest_id)from base_data_login_info@agent awhere a.str_day <= '20160304'and a.str_day >= '20160301'and a.channel_id in (select channel_rlatfrom tb_user_channel a, tb_channel_info bwhere a.channel_id = b.channel_idand a.user_id = 5002)and a.platform = a.platform;又秒杀了,卧槽,我感觉女神就在我面前了,我再加一个distinct看看还能不能秒杀select count(distinct a.user_name), count(distinct a.invest_id)from base_data_login_info@agent awhere a.str_day <= '20160304'and a.str_day >= '20160301'and a.channel_id in (select channel_rlatfrom tb_user_channel a, tb_channel_info bwhere a.channel_id = b.channel_idand a.user_id = 5002)and a.platform = a.platform;这次死了,SQL跑不动了,太他妈奇葩了,看文章的兄弟们,你们觉得是不是很奇葩。说了这么多,遇到这种奇葩的问题怎么解决呢?首先要解决问题啊,不能让这个SQL跑得慢,搞不定问题,那哥也不用混了,道森也不用开了,倒闭得了。其次嘛再找出根本问题,防止下一次遇到同类问题,顺便也让网友看看我写的案例,各位网友就当黄色小说看看得了。先来解决这个问题,给了兄弟下面这个SQLwith t1 as 
(select /*+ materialize */a.user_name, a.invest_idfrom base_data_login_info@agent awhere a.str_day <= '20160304' and a.str_day >= '20160301'and a.channel_id in (select channel_rlat from tb_user_channel a, tb_channel_info b where a.channel_id = b.channel_id and a.user_id = 5002)and a.platform = a.platform)
select count(distinct user_name) ,count(distinct invest_id) from t1;Plan hash value: 901326807-----------------------------------------------------------------------------------------------------------------------
| Id  | Operation                  | Name                     | Rows  | Bytes | Cost (%CPU)| Time     | Inst   |IN-OUT|
-----------------------------------------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT           |                          |     1 |    54 |  1621   (1)| 00:00:20 |        |      |
|   1 |  TEMP TABLE TRANSFORMATION |                          |       |       |            |          |        |      |
|   2 |   LOAD AS SELECT           | SYS_TEMP_0FD9D6720_EB8EA |       |       |            |          |        |      |
|*  3 |    HASH JOIN RIGHT SEMI    |                          |   190K|    22M|   744   (1)| 00:00:09 |        |      |
|   4 |     VIEW                   | VW_NSO_1                 | 11535 |   304K|   258   (1)| 00:00:04 |        |      |
|*  5 |      HASH JOIN             |                          | 11535 |   360K|   258   (1)| 00:00:04 |        |      |
|*  6 |       TABLE ACCESS FULL    | TB_USER_CHANNEL          | 11535 |   157K|    19   (0)| 00:00:01 |        |      |
|   7 |       TABLE ACCESS FULL    | TB_CHANNEL_INFO          | 11767 |   206K|   238   (0)| 00:00:03 |        |      |
|   8 |     REMOTE                 | BASE_DATA_LOGIN_INFO     |   190K|    17M|   486   (1)| 00:00:06 |  AGENT | R->S |
|   9 |   SORT GROUP BY            |                          |     1 |    54 |            |          |        |      |
|  10 |    VIEW                    |                          |   190K|     9M|   878   (1)| 00:00:11 |        |      |
|  11 |     TABLE ACCESS FULL      | SYS_TEMP_0FD9D6720_EB8EA |   190K|     9M|   878   (1)| 00:00:11 |        |      |
-----------------------------------------------------------------------------------------------------------------------Predicate Information (identified by operation id):
---------------------------------------------------3 - access("A"."CHANNEL_ID"="CHANNEL_RLAT")5 - access("A"."CHANNEL_ID"="B"."CHANNEL_ID")6 - filter("A"."USER_ID"=5002)Remote SQL Information (identified by operation id):
----------------------------------------------------8 - SELECT "USER_NAME","INVEST_ID","STR_DAY","CHANNEL_ID","PLATFORM" FROM "BASE_DATA_LOGIN_INFO" "A" WHERE "STR_DAY"<='20160304' AND "STR_DAY">='20160301' AND "PLATFORM" IS NOT NULL (accessing 'AGENT' )SQL秒杀了。 with as /*+ materialize */  这个绝招 道森的人都知道。不信你看我博客去啊(百度 csdn 落落的专栏)。我估计过不了多久整个 数据库圈的人全都知道了。光解决问题,那不行啊,必须找出问题根本原因啊,这样才好装逼装大神装大师嘛。首先从执行计划上分析跑得快的SQL以及执行计划 select count(a.user_name), count(distinct a.invest_id)from base_data_login_info@agent awhere a.str_day <= '20160304'and a.str_day >= '20160301'and a.channel_id in (select channel_rlatfrom tb_user_channel a, tb_channel_info bwhere a.channel_id = b.channel_idand a.user_id = 5002)and a.platform = a.platformPlan hash value: 4282421321------------------------------------------------------------------------------------------------------------------------
| Id  | Operation               | Name                 | Rows  | Bytes |TempSpc| Cost (%CPU)| Time     | Inst   |IN-OUT|
------------------------------------------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT        |                      |     1 |    40 |       |  2982   (1)| 00:00:36 |        |      |
|   1 |  SORT AGGREGATE         |                      |     1 |    40 |       |            |          |        |      |
|   2 |   VIEW                  | VW_DAG_0             | 41456 |  1619K|       |  2982   (1)| 00:00:36 |        |      |
|   3 |    HASH GROUP BY        |                      | 41456 |  4250K|    20M|  2982   (1)| 00:00:36 |        |      |
|*  4 |     HASH JOIN RIGHT SEMI|                      |   190K|    19M|       |   744   (1)| 00:00:09 |        |      |
|   5 |      VIEW               | VW_NSO_1             | 11535 | 80745 |       |   258   (1)| 00:00:04 |        |      |
|*  6 |       HASH JOIN         |                      | 11535 |   360K|       |   258   (1)| 00:00:04 |        |      |
|*  7 |        TABLE ACCESS FULL| TB_USER_CHANNEL      | 11535 |   157K|       |    19   (0)| 00:00:01 |        |      |
|   8 |        TABLE ACCESS FULL| TB_CHANNEL_INFO      | 11767 |   206K|       |   238   (0)| 00:00:03 |        |      |
|   9 |      REMOTE             | BASE_DATA_LOGIN_INFO |   190K|    17M|       |   486   (1)| 00:00:06 |  AGENT | R->S |
------------------------------------------------------------------------------------------------------------------------Predicate Information (identified by operation id):
---------------------------------------------------4 - access("A"."CHANNEL_ID"="CHANNEL_RLAT")6 - access("A"."CHANNEL_ID"="B"."CHANNEL_ID")7 - filter("A"."USER_ID"=5002)Remote SQL Information (identified by operation id):
----------------------------------------------------9 - SELECT "USER_NAME","INVEST_ID","STR_DAY","CHANNEL_ID","PLATFORM" FROM "BASE_DATA_LOGIN_INFO" "A" WHERE "STR_DAY"<='20160304' AND "STR_DAY">='20160301' AND "PLATFORM" IS NOT NULL (accessing 'AGENT' )跑得慢的SQL以及执行计划select count(distinct a.user_name), count(distinct a.invest_id)from base_data_login_info@agent awhere a.str_day <= '20160304'and a.str_day >= '20160301'and a.channel_id in (select channel_rlatfrom tb_user_channel a, tb_channel_info bwhere a.channel_id = b.channel_idand a.user_id = 5002)and a.platform = a.platformPlan hash value: 2367445948-------------------------------------------------------------------------------------------------------------
| Id  | Operation            | Name                 | Rows  | Bytes | Cost (%CPU)| Time     | Inst   |IN-OUT|
-------------------------------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT     |                      |     1 |   130 |   754   (2)| 00:00:10 |        |      |
|   1 |  SORT GROUP BY       |                      |     1 |   130 |            |          |        |      |
|*  2 |   HASH JOIN          |                      |  4067K|   504M|   754   (2)| 00:00:10 |        |      |
|*  3 |    HASH JOIN         |                      | 11535 |   360K|   258   (1)| 00:00:04 |        |      |
|*  4 |     TABLE ACCESS FULL| TB_USER_CHANNEL      | 11535 |   157K|    19   (0)| 00:00:01 |        |      |
|   5 |     TABLE ACCESS FULL| TB_CHANNEL_INFO      | 11767 |   206K|   238   (0)| 00:00:03 |        |      |
|   6 |    REMOTE            | BASE_DATA_LOGIN_INFO |   190K|    17M|   486   (1)| 00:00:06 |  AGENT | R->S |
-------------------------------------------------------------------------------------------------------------Predicate Information (identified by operation id):
---------------------------------------------------2 - access("A"."CHANNEL_ID"="CHANNEL_RLAT")3 - access("A"."CHANNEL_ID"="B"."CHANNEL_ID")4 - filter("A"."USER_ID"=5002)Remote SQL Information (identified by operation id):
----------------------------------------------------6 - SELECT "USER_NAME","INVEST_ID","STR_DAY","CHANNEL_ID","PLATFORM" FROM "BASE_DATA_LOGIN_INFO" "A" WHERE "STR_DAY"<='20160304' AND "STR_DAY">='20160301' AND "PLATFORM" IS NOT NULL (accessing 'AGENT' )       如果没有优化过几千几万个SQL,哪里能练出火眼金睛,注意看跑得慢的SQL是HASH JOIN,跑得快的SQL是 HASH JOIN RIGHT SEMI也就是说跑得慢的SQL是 HASH JOIN(inner join),跑得快的 SQL 是 HASH SEMI JOIN (semi join) 说人话就是跑得慢的SQL变成内连接了,跑得快的SQL是半连接(in/exists)。明明SQL是半连接啊,咋变成内连接了呢,这涉及到优化器内部原理和大学课程里面的关系代数了这里就不装逼了,免得到时候一个个看不懂来问我烦死了。问题又来了,就几万跟十几万的进行HASH JOIN 应该很快啊,如果跑的慢那只有一个解释,2个表的关联列数据分布都非常不均衡 19W 表连接列SQL> select channel_id,count(*) from base_data_login_info group by channel_id order by 2;CHANNEL_ID               COUNT(*)
-------------------------------------------------- ----------
011a1                 2
003a1                 3
021a1                 3
006a1                12
024h2                16
013a1                19
007a1                24
012a1                25
005a1                27
EPT01                36
028h2               109
008a1               139
029a1               841
009a1               921
014a1              1583
000a1              1975
a0001              2724
004a1              5482
001a1             16329
026h2             160162in里面的关联列数据分布select channel_rlat, count(*)from tb_user_channel a, tb_channel_info bwhere a.channel_id = b.channel_idand a.user_id = 5002group by channel_rlatorder by 2 descchannel_rlat  count(*)
026h2         10984
024h2         7
002h2         6
023a2         2
007s001022001 1
007s001022002 1
007s001024007 1
007s001024009 1
007s001022009 1
001s001006    1
001s001008    1
001s001001001 1
001s001001003 1
001s001001007 1
001s001001014 1
007s001018003 1
007s001018007 1
007s001019005 1
007s001019008 1
001s001002011 1
007s001011003 1
007s001034    1
007s001023005 1果然,不出本大仙所料,这尼玛走内连接的 HASH JOIN 不死人才怪 
026h2             160162 与 026h2         10984 进行关联完全就是一个笛卡尔积10046 trace 文件已经 告诉了答案 HASH JOIN 返回 410996039  ,这尼玛就是一个小型笛卡尔积了  Rows (1st) Rows (avg) Rows (max)  Row Source Operation
---------- ---------- ----------  ---------------------------------------------------1          1          1  SORT GROUP BY (cr=3643 pr=0 pw=0 time=1236559678 us)410996039  410996039  410996039   HASH JOIN  (cr=3643 pr=0 pw=0 time=406365130 us cost=1006 size=66968010 card=458685)11535      11535      11535    HASH JOIN  (cr=945 pr=0 pw=0 time=199182 us cost=258 size=369120 card=11535)11535      11535      11535     TABLE ACCESS FULL TB_USER_CHANNEL (cr=67 pr=0 pw=0 time=21452 us cost=19 size=161490 card=11535)11771      11771      11771     TABLE ACCESS FULL TB_CHANNEL_INFO (cr=878 pr=0 pw=0 time=30291 us cost=238 size=211806 card=11767)45122      45122      45122    TABLE ACCESS FULL BASE_DATA_LOGIN_INFO (cr=2698 pr=0 pw=0 time=218144 us cost=747 size=2447922 card=21473)看不懂的人可以做个实验create table a as select * from dba_objects;create table b as select * from dba_objects;然后你去跑下面的SQL,慢慢等结果把select count(distinct owner), count(distinct object_name)from awhere owner in (select owner from b);然而你跑下面这些SQL都可以秒杀select count(owner), count(distinct object_name)from awhere owner in (select owner from b);select count(distinct owner), count(distinct object_name)from awhere object_id in (select object_id from b);那么怎么对跑得慢的SQL进行等价改写呢?select count(distinct owner), count(distinct object_name)from awhere owner in (select owner from b);答案如下:select count(distinct owner), count(distinct object_name)from (select owner, object_namefrom awhere owner in (select owner from b)and rownum > 0);
思考为啥11g CBO会 改写为 inner join 呢? 
select xxx from 1的表  where owner in (select owner from n 的表) 改写为 inner join 前面不需要加 distinct
select xxx from n的表  where owner in (select owner from 1的表) 改写为 inner join 前面要加 distinct 
我们的SQL 是 select count(distinct ),count(distinct) 
所以 CBO 直接改写为 select count(distinct a.owner),count(distinct object_name) from a,b where a.owner=b.owner;
这样就引起了 小笛卡尔积,所以就慢了 那么这个问题在 12c里面被纠正了,有兴趣自己玩个12c 试一试
不管优化器多聪明,始终没有人聪明 看不懂这篇文章的人努力吧

 

这篇关于数据分布不均衡导致性能问题的文章就介绍到这儿,希望我们推荐的文章对编程师们有所帮助!



http://www.chinasem.cn/article/182356

相关文章

怎样通过分析GC日志来定位Java进程的内存问题

《怎样通过分析GC日志来定位Java进程的内存问题》:本文主要介绍怎样通过分析GC日志来定位Java进程的内存问题,具有很好的参考价值,希望对大家有所帮助,如有错误或未考虑完全的地方,望不吝赐教... 目录一、GC 日志基础配置1. 启用详细 GC 日志2. 不同收集器的日志格式二、关键指标与分析维度1.

Java 线程安全与 volatile与单例模式问题及解决方案

《Java线程安全与volatile与单例模式问题及解决方案》文章主要讲解线程安全问题的五个成因(调度随机、变量修改、非原子操作、内存可见性、指令重排序)及解决方案,强调使用volatile关键字... 目录什么是线程安全线程安全问题的产生与解决方案线程的调度是随机的多个线程对同一个变量进行修改线程的修改操

Redis出现中文乱码的问题及解决

《Redis出现中文乱码的问题及解决》:本文主要介绍Redis出现中文乱码的问题及解决,具有很好的参考价值,希望对大家有所帮助,如有错误或未考虑完全的地方,望不吝赐教... 目录1. 问题的产生2China编程. 问题的解决redihttp://www.chinasem.cns数据进制问题的解决中文乱码问题解决总结

全面解析MySQL索引长度限制问题与解决方案

《全面解析MySQL索引长度限制问题与解决方案》MySQL对索引长度设限是为了保持高效的数据检索性能,这个限制不是MySQL的缺陷,而是数据库设计中的权衡结果,下面我们就来看看如何解决这一问题吧... 目录引言:为什么会有索引键长度问题?一、问题根源深度解析mysql索引长度限制原理实际场景示例二、五大解决

Springboot如何正确使用AOP问题

《Springboot如何正确使用AOP问题》:本文主要介绍Springboot如何正确使用AOP问题,具有很好的参考价值,希望对大家有所帮助,如有错误或未考虑完全的地方,望不吝赐教... 目录​一、AOP概念二、切点表达式​execution表达式案例三、AOP通知四、springboot中使用AOP导出

Python中Tensorflow无法调用GPU问题的解决方法

《Python中Tensorflow无法调用GPU问题的解决方法》文章详解如何解决TensorFlow在Windows无法识别GPU的问题,需降级至2.10版本,安装匹配CUDA11.2和cuDNN... 当用以下代码查看GPU数量时,gpuspython返回的是一个空列表,说明tensorflow没有找到

解决未解析的依赖项:‘net.sf.json-lib:json-lib:jar:2.4‘问题

《解决未解析的依赖项:‘net.sf.json-lib:json-lib:jar:2.4‘问题》:本文主要介绍解决未解析的依赖项:‘net.sf.json-lib:json-lib:jar:2.4... 目录未解析的依赖项:‘net.sf.json-lib:json-lib:jar:2.4‘打开pom.XM

IDEA Maven提示:未解析的依赖项的问题及解决

《IDEAMaven提示:未解析的依赖项的问题及解决》:本文主要介绍IDEAMaven提示:未解析的依赖项的问题及解决,具有很好的参考价值,希望对大家有所帮助,如有错误或未考虑完全的地方,望不吝... 目录IDEA Maven提示:未解析的依编程赖项例如总结IDEA Maven提示:未解析的依赖项例如

Redis分片集群、数据读写规则问题小结

《Redis分片集群、数据读写规则问题小结》本文介绍了Redis分片集群的原理,通过数据分片和哈希槽机制解决单机内存限制与写瓶颈问题,实现分布式存储和高并发处理,但存在通信开销大、维护复杂及对事务支持... 目录一、分片集群解android决的问题二、分片集群图解 分片集群特征如何解决的上述问题?(与哨兵模

SpringBoot+Redis防止接口重复提交问题

《SpringBoot+Redis防止接口重复提交问题》:本文主要介绍SpringBoot+Redis防止接口重复提交问题,具有很好的参考价值,希望对大家有所帮助,如有错误或未考虑完全的地方,望不... 目录前言实现思路代码示例测试总结前言在项目的使用使用过程中,经常会出现某些操作在短时间内频繁提交。例