关于java之中死锁会不会占用系统资源

RT代码如下:

public class AnotherDeadLock { 

  public static void main(String[] args) { 

    final Object resource1 = "resource1"; 

    final Object resource2 = "resource2"; 

    // t1 tries to lock resource1 then resource2 

    Thread t1 = new Thread() { 

      public void run() { 

        // Lock resource 1 

        synchronized (resource1) { 

          System.out.println("Thread 1: locked resource 1"); 

          try { 

            Thread.sleep(50); 

          } catch (InterruptedException e) { 

          } 

          synchronized (resource2) { 

            System.out.println("Thread 1: locked resource 2"); 

          } 

        } 

      } 

    }; 

    // t2 tries to lock resource2 then resource1 

    Thread t2 = new Thread() { 

      public void run() { 

        synchronized (resource2) { 

          System.out.println("Thread 2: locked resource 2"); 

          try { 

            Thread.sleep(50); 

          } catch (InterruptedException e) { 

          } 

          synchronized (resource1) { 

            System.out.println("Thread 2: locked resource 1"); 

          } 

        } 

      } 

    }; 

    // If all goes as planned, deadlock will occur, 

    // and the program will never exit. 

    t1.start(); 

    t2.start(); 

  } 

}

各位可以自己试一试，有点儿疑惑(因为老师上课讲的是死锁会引发系统资源居高不下)，

然后在德问社区中发帖求助，有大神回答如下：

源：http://www.dewen.org/q/13297/%E7%BA%BF%E7%A8%8B%E6%AD%BB%E9%94%81%E6%98%AF%E4%B8%8D%E6%98%AFcpu%E8%B5%84%E6%BA%90%E4%B8%80%E5%AE%9A%E4%BC%9A%E5%B1%85%E9%AB%98%E4%B8%8D%E4%B8%8B#24104