licode做题记录

1、Ascii码转换：

    public static void main(String[] args) {String a = "Z";// 其中A~Z表示65~90; a~z表示97~122// 字符转换成数字(int类型)int asc_Num = (int)a.getBytes()[0];int num = 65;// 数字转换成字符(char类型)char asc_char = (char)num;System.out.println(asc_Num+"  "+asc_char);}

import java.util.Scanner;public class UserName {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);  //输入int num = scanner.nextInt();for (int i=0; i<num; i++){String a = scanner.next();boolean name_legal = judgeName(a);//如果用户名合法，请输出 "Accept"，反之输出 "Wrong"if (name_legal==true){System.out.println("Accept");}else {System.out.println("Wrong");}}}//方法：是否合法public static boolean judgeName(String name){// 其中A~Z表示65~90; a~z表示97~122; 1~9的Asc码：49~57boolean judgeFirstChar = false;// 条件一：用户名的首字符必须是大写或者小写字母。int asc_Num = (int)name.getBytes()[0];if (asc_Num>=65&&asc_Num<=90||asc_Num>=97&&asc_Num<=122){judgeFirstChar = true;}else {  //如果不满足条件一return false;}// 条件二：遍历字符串int int_num = 0;int char_num = 0;for (int i = 0; i < name.length(); i++){char c = name.charAt(i); // 获取字符串的字符int asc_num = (int)c;if (asc_Num>=65&&asc_Num<=90||asc_Num>=97&&asc_Num<=122||asc_Num>=49&&asc_Num<=57){if (asc_Num>=49&&asc_Num<=57){int_num++;}else {char_num++;}}else { //如果不满足条件二的话return false;}}// 条件三：判断至少一个字母和一个数字if (judgeFirstChar==true&&int_num>=1&&char_num>=1){return true;}else {return false;}}
}