Python装逼代码

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前言

今天，我们来做两个可以装逼的代码。

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一、黑客帝国

做这个需要有pygame库。

首先导入库

import random
import pygame

代码部分：
 

import random
import pygame
PANEL_width = 600
PANEL_highly = 500
FONT_PX = 15
pygame.init()
winSur = pygame.display.set_mode((PANEL_width, PANEL_highly))
font = pygame.font.SysFont("123.ttf", 25)
bg_suface = pygame.Surface((PANEL_width, PANEL_highly), flags=pygame.SRCALPHA)
pygame.Surface.convert(bg_suface)
bg_suface.fill(pygame.Color(0, 0, 0, 28))
winSur.fill((0, 0, 0))
letter = ['q', 'w', 'e', 'r', 't', 'y', 'u', 'i', 'o', 'p', 'a', 's', 'd', 'f', 'g', 'h', 'j', 'k', 'l', 'z', 'x', 'c','v', 'b', 'n', 'm']
texts = [font.render(str(letter[i]), True, (0, 255, 0)) for i in range(26)
]
column = int(PANEL_width / FONT_PX)
drops = [0 for i in range(column)]
while True:for event in pygame.event.get():if event.type == pygame.QUIT:exit()elif event.type == pygame.KEYDOWN:chang = pygame.key.get_pressed()if(chang[32]):exit()pygame.time.delay(30)winSur.blit(bg_suface, (0, 0))for i in range(len(drops)):text = random.choice(texts)winSur.blit(text, (i * FONT_PX, drops[i] * FONT_PX))drops[i] += 1if drops[i] * 10 > PANEL_highly or random.random() > 0.95:drops[i] = 0pygame.display.flip()

 

二、病毒弹窗

导入库：
 

import tkinter as tk
import random
import threading
import time
代码：import tkinter as tk
import random
import threading
import time
color = ['red', '#356F9F']
color1 = random.choices(color)
def dow():window = tk.Tk()width = window.winfo_screenwidth()height = window.winfo_screenheight()a = random.randrange(0, width)b = random.randrange(0, height)window.title('Python') window.geometry("200x200" + "+" + str(a) + "+" + str(b)) tk.Label(window,text='病毒',  bg=color1, font=('楷体', 17),  width=15, height=10 ).pack() window.mainloop()
threads = []
for i in range(1400): t = threading.Thread(target=dow)threads.append(t)time.sleep(0.0000000000000000000001)threads[i].start()

text='病毒'
这里是可以改的。 

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