本文主要是介绍273整数转换英文表示，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！
1、题目描述
将非负整数转换为其对应的英文表示。可以保证给定输入小于 2^31 - 1 。
2、示例
输入: 1234567891
输出: "One Billion Two Hundred Thirty Four Million Five Hundred Sixty Seven Thousand Eight Hundred Ninety One"
3、题解
#include<vector>
#include<algorithm>
#include<iostream>
#include<string>
using namespace std;
class Solution {
public:string numberToWords(int num) {if(num==0)return "Zero";vector<string> dict={"Hundred","Thousand","Million","Billion"};vector<string> number={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};vector<string> teen={"Ten","Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"};vector<string> ty={"Twenty","Thirty","Forty","Fifty","Sixty","Seventy","Eighty","Ninety"};string res;int i=0;//1,234,567,891 英文计数都是3个一组分别是Thousand,Million,Billionwhile(num){int temp=num%1000;string cur;//flag标记当前组是否有数字，如果没有数字就不用加Thousand,Million,Billion及空格//space标记百位是否有数字，如果没有，防止多余空格出现int flag=0,space=0;//提取百位转化为字符串if(temp/100){flag=1;space=1;cur.append(number[temp/100-1]);cur.append(" ");cur.append(dict[0]);temp%=100;}//提取十位和个位转化为字符串//十位是1开头if(temp/10==1){flag=1;if(space)cur.append(" ");cur.append(teen[temp%10]);}//十位是2-9开头else if(temp/10>1){flag=1;if(space)cur.append(" ");cur.append(ty[temp/10-2]);if(temp%10){cur.append(" ");cur.append(number[temp%10-1]);}}//十位是0，就只有个位else{if(temp%10){flag=1;if(space)cur.append(" ");cur.append(number[temp%10-1]);}}//3个一组分别是Thousand,Million,Billion，以及该组是否有数字才加上if(i>0&&flag){cur.append(" ");cur.append(dict[i]);cur.append(" ");}//当前组的字符串cur拼接到resres=cur+res;num/=1000;i++;}//去掉开头和末尾多余的空格if(res[0]==' ')res=res.substr(1,res.size()-1);if(res.back()==' ')res=res.substr(0,res.size()-1);return res;}
};
int main()
{Solution solute;int num=1234567891;cout<<solute.numberToWords(num)<<endl;return 0;
}
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