通过Python脚本批量复制并规范命名视频文件

import os
import re
import shutil

def rename_and_copy_mp4_files(source_dir, target_dir):
    """智能重命名并复制视频文件
    
    Args:
        source_dir (str): 源目录路径
        target_dir (str): 目标目录路径
    """
    # 创建目标目录（自动处理已存在情况）
    os.makedirs(target_dir, exist_ok=True)
    
    # 遍历源目录所有文件
    for filename in os.listdir(source_dir):
        # 使用正则表达式解析文件名
        pattern_match = re.match(r'\[(\d+)\](.+)\.(mp4|avi|mov)$', filename, re.IGphpNORECASE)
        
        if pattern_match:
            # 提取文件名组件
            file_number = pattern_match.group(1)
            file_content = pattern_match.group(2).strip()
            file_ext = pattern_match.group(3).lower()
            
            # 格式化数字编号（4位补零）
            formatted_number = file_number.zfill(4)
            
            # 构建新文件名
            new_filename = f"{formatted_number}_{file_content}.{file_ext}"
            
            # 构建完整路径
            src_path = os.path.join(source_dir, filename)
            dst_path = os.path.join(target_dir, new_filename)
            
            # 执行带元数据的复制China编程操作
            shutil.copy2(src_path, dst_path)
            print(f"成功处理：{filename} → {new_filename}")
        else:
            print(f"跳过非标准文件：{filename}")

if __name__ == "__main__":
    # 配置路径（根据实际情况修改）
    SOURCE_DIR = r"E:\video_source"
    TARGET_DIR = r"E:\video_organized"
    
    rename_and_copy_mChina编程p4_files(SOURCE_DIR, TARGET_DIR)

os.makedirs(target_dir, exist_ok=True)

r'\[(\d+)\](.+)\.(mp4|avi|mov)$'

file_number.zfill(4)

shutil.copy2(srjsc, dst)

# Windows系统示例
SOURCE_DIR = r"E:\training_videos"
TARGET_DIR = r"D:\sorted_videos"

# MACOS/linux示例
# SOURCE_DIR = "/Users/username/Videos/source"
# TARGET_DIR = "/Volumes/external_drive/sorted_videos"

# 在循环开始前添加
total_files = len([f for f in os.listdir(source_dir) if f.endswith(('.mp4', '.avi', '.mov'))])
processed = 0

# 在处理成功时添加
processed += 1
print(f"进度：{processed}/{total_files} ({processed/total_files:.1%})")

if os.path.exists(dst_path):
    base, ext = os.path.splitext(new_filename)
    counter = 1
    while os.path.exists(dst_path):
        new_filename = f"{base}_{counter}{ext}"
        dst_path = os.path.join(target_dir, new_filename)
        counter += 1

from concurrent.futures import ThreadPoolExecutor

def process_file(filename):
    # 原处理逻辑

with ThreadPoolExecutor(max_workers=4) as executor:
    executor.map(process_file, os.listdir(source_dir))

file_content = re.sub(r'[<>:"/\\|?*]', '', file_content)