简单封装一个类似菜单栏的树状结构转换

本文主要是介绍简单封装一个类似菜单栏的树状结构转换，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

充血的菜单实体类

@Data
public class Menu {public Integer id;public String name;public Integer parentId;// 根节点为0public List<Menu> childList;public Menu(Integer id, String name, Integer parentId) {this.id = id;this.name = name;this.parentId = parentId;this.childList = new ArrayList<>();}public static List<Menu> selectAll() {return Arrays.asList(new Menu(1, "根节点", 0),new Menu(2, "子节点1", 1),new Menu(3, "子节点1.1", 2),new Menu(4, "子节点1.2", 2),new Menu(5, "根节点1.3", 2),new Menu(6, "根节点2", 1),new Menu(7, "根节点2.1", 6),new Menu(8, "根节点2.2", 6),new Menu(9, "根节点2.2.1", 7),new Menu(10, "根节点2.2.2", 7),new Menu(11, "根节点3", 1),new Menu(12, "根节点3.1", 11));}
}

先做实现

public class Test {public static void main(String[] args) {List<Menu> menuList = Menu.selectAll();// 1：遍历(O(n))节点并查找(O(1))加入父节点。总复杂度为O(n)。Map<Integer, Menu> menuMap = menuList.stream().collect(Collectors.toMap(Menu::getId, menu -> menu));menuMap.forEach((key, value) -> {if (value.getParentId() == 0) return; // 根节点不处理menuMap.get(value.getParentId()).getChildList().add(value);});Menu root = menuMap.get(1);System.out.println(root);}
}

封装一下，主要抽象了实体类的ID、父节点ID、子节点列表这三个字段的Getter

public class Test {public static void main(String[] args) {List<Menu> menuList = Menu.selectAll();// 抽象class Tree<T>{public T parse(List<T> list, Function<T, Integer> getId, Function<T,Integer> getParentId, Function<T, Collection<T>> getChildList) {Map<Integer, T> map = list.stream().collect(Collectors.toMap(getId, t -> t));map.forEach((key, value) -> {if (getParentId.apply(value) == 0) return; // 根节点不处理getChildList.apply(map.get(getParentId.apply(value))).add(value);});return map.get(1);}}Menu root = new Tree<Menu>().parse(menuList, Menu::getId, Menu::getParentId, Menu::getChildList);System.out.println(root);}
}

再封装一下，把根节点的判断条件封装了

public class Test {public static void main(String[] args) {List<Menu> menuList = Menu.selectAll();// 抽象class Tree<T>{public T parse(List<T> list, Function<T, Integer> getId, Function<T,Integer> getParentId, Function<T, Collection<T>> getChildList,Function<T,Boolean> isRoot) {AtomicReference<T> root = new AtomicReference<>();Map<Integer, T> map = list.stream().collect(Collectors.toMap(getId, t -> t));map.forEach((key, value) -> {if (isRoot.apply(value)) {root.set(value);return; // 根节点不处理}getChildList.apply(map.get(getParentId.apply(value))).add(value);});return root.get();}}Menu root = new Tree<Menu>().parse(menuList, Menu::getId, Menu::getParentId, Menu::getChildList, menu -> menu.getParentId() == 0);System.out.println(root);}
}

再再封装，类泛型有点大，改为方法泛型吧

public class Test {public static void main(String[] args) {List<Menu> menuList = Menu.selectAll();// 抽象class Tree {public static <T> T parse(List<T> list, Function<T, Integer> getId, Function<T,Integer> getParentId, Function<T, Collection<T>> getChildList,Function<T,Boolean> isRoot) {AtomicReference<T> root = new AtomicReference<>();Map<Integer, T> map = list.stream().collect(Collectors.toMap(getId, t -> t));map.forEach((key, value) -> {if (isRoot.apply(value)) {root.set(value);return; // 根节点不处理}getChildList.apply(map.get(getParentId.apply(value))).add(value);});return root.get();}}Menu root = Tree.parse(menuList, Menu::getId, Menu::getParentId, Menu::getChildList, menu -> menu.getParentId() == 0);System.out.println(root);}
}